Kurosaki Akatsu Coordinator
09/03/2017 at 21:31-
mathlove 09/03/2017 at 22:26Set \(\dfrac{a}{a'}=\dfrac{b}{b'}=\dfrac{c}{c'}=k\). We have \(k=\dfrac{ax^2}{a'x^2}=\dfrac{bx}{b'x}=\dfrac{c}{c'}=\dfrac{ax^2+bx+c}{a'x^2+b'x+c}=P\).
So that \(P=k,\forall x\) . So \(P\) does not depend on \(x\) .
Kurosaki Akatsu selected this answer. -
FA FIFA Club World Cup 2018 16/01/2018 at 21:58Set aa′=bb′=cc′=k. We have k=ax2a′x2=bxb′x=cc′=ax2+bx+ca′x2+b′x+c=P
.
So that P=k,∀x
. So P does not depend on x .
