Asuna Yuuki
09/03/2017 at 21:44-
Give A = 22 + 24 + .... + 2100
4A = 24 + .... + 2100 + 2102
4A - A = (24 + .... + 2100 + 2102) - (22 + 24 + .... + 2100)
3A = 2102 - 22
A = \(\dfrac{2^{102}-4}{3}\)
Asuna Yuuki selected this answer. -
Vũ Thị Hương Giang 09/03/2017 at 21:47Ta có : A = 22 + 24 + 26 + ...... + 2100
=> 22A = 24 + 26 + ...... + 2100 + 2102
=> 4A - A = 2102 - 22
=> 3A = 2102 - 4
=> A = \(\dfrac{2^{102}-4}{3}\)
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demo acc 10/03/2017 at 14:44very good
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FA FIFA Club World Cup 2018 16/01/2018 at 22:03Give A = 22 + 24 + .... + 2100
4A = 24 + .... + 2100 + 2102
4A - A = (24 + .... + 2100 + 2102) - (22 + 24 + .... + 2100)
3A = 2102 - 22
A = 2102−43
