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Nguyễn Việt Hoàng 10/03/2017 at 11:24We have x + x2 + x3 + ..... + x100
At x = 1 then x + x2 + x3 + ..... + x100
= 1 + 12 + 13 + ...... + 1100
= 1 + 1 + 1 + ..... + 1
= 1 x 100
= 100
Mathlike selected this answer. -
Trịnh Đức Phát 22/03/2017 at 12:50We have x + x2 + x3 + ..... + x100
At x = 1 then x + x2 + x3 + ..... + x100
= 1 + 12 + 13 + ...... + 1100
= 1 + 1 + 1 + ..... + 1
= 1 x 100
= 100
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FA FIFA Club World Cup 2018 16/01/2018 at 22:06We have x + x2 + x3 + ..... + x100
At x = 1 then x + x2 + x3 + ..... + x100
= 1 + 12 + 13 + ...... + 1100
= 1 + 1 + 1 + ..... + 1
= 1 x 100
= 100
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x + x2 + x3 + ..... + x100 with x = 1
=> 1 + 12 + 13 + .... + 1100
=> 1 + 1 + 1 + .... + 1 (100 number)
=> 1 x 100 = 100
=> x + x2 + x3 + ..... + x100 = 100
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nguyenhue24032004 10/03/2017 at 11:24Give A=x+x2+x3+..+x100
A=1+12+13+...+1100
A=1+1+1+...+1 ( 100 number 1)
A=100
So the expression x+x2+x3+...+x100 at x=1 is 100
