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equality

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FA Thần Tốc Độ
08/02/2018 at 21:46
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For a + b + c = 0 . Prove that : \(a^3+b^3+c^3=0\)

equality


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Summer Clouds moderators
16/07/2017 at 12:10
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Give \(\dfrac{a}{b}=\dfrac{a}{d}\), Prove that \(\dfrac{2a-3c}{2b-3d}=\dfrac{2a+3c}{2b+3d}\)

equality

  • ...
    Kayasari Ryuunosuke Coordinator 16/07/2017 at 12:47

    Convert  \(\dfrac{a}{b}=\dfrac{a}{d}\) to \(\dfrac{a}{b}=\dfrac{c}{d}\)

    We have :

    \(\dfrac{a}{b}=\dfrac{c}{d}\Leftrightarrow\dfrac{2a}{2b}=\dfrac{3c}{3d}\)

    Apply the same sequence properties , we got :

    \(\dfrac{2a}{2b}=\dfrac{3c}{3d}=\dfrac{2a-3c}{2b-3d}=\dfrac{2a+3c}{2b+3d}\)

    \(\Rightarrow\dfrac{2a-3c}{2b-3d}=\dfrac{2a+3c}{2b+3d}\)

  • ...
    Trần Nhật Dương 16/07/2017 at 17:16
     

    Convert  a/b=a/d to a/b=c/d

    We have :

    a/b=c/d⇔2a/2b=3c/3d

    Apply the same sequence properties , we got :

    2a/2b=3c/3d=2a−3c/2b−3d=2a+3c/2b+3d

    ⇒2a−3c/2b−3d = 2a + 3c/2b + 3d

  • ...
    v 16/07/2017 at 12:35

    \(\dfrac{a}{b}=\dfrac{c}{d}\Rightarrow\dfrac{2a}{2b}=\dfrac{3c}{3d}=\dfrac{2a+3c}{2b+3d}=\dfrac{2a-3c}{2b-3d}\)


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