Sentence 1: Thanksgiving is always the last Thursday of November

Sentence 1: Thanksgiving is always the last Thursday of November

Boomer

RONALDO HẢ?

tan(a)=12⇔a=26,5605118

⇒tan(90−2a)=tan(90−2⋅26,56505118)=34

tan(a)=12⇔a=26,5605118

⇒tan(90−2a)=tan(90−2⋅26,56505118)=34

Dao Trong Luan:Why? tan(a)=\(\dfrac{1}{2}\) can \(\Rightarrow a=26,5605118\)

This is you use calculator for calculate

That number is 322

\(That\) \(number\) \(is\) \(322\)

i think is 322

Use AM-GM's ineq:

\(\dfrac{b+c}{\sqrt{a}}+\dfrac{c+a}{\sqrt{b}}+\dfrac{a+b}{\sqrt{c}}\ge\dfrac{2\sqrt{bc}}{\sqrt{a}}+\dfrac{2\sqrt{ca}}{\sqrt{b}}+\dfrac{2\sqrt{ab}}{\sqrt{c}}\)

\(=\left(\sqrt{\dfrac{bc}{a}}+\sqrt{\dfrac{ca}{b}}\right)+\left(\sqrt{\dfrac{ca}{b}}+\sqrt{\dfrac{ab}{c}}\right)+\left(\sqrt{\dfrac{ab}{c}}+\sqrt{\dfrac{bc}{a}}\right)\)

\(\ge\sqrt{a}+\sqrt{b}+\sqrt{c}+\sqrt{a}+\sqrt{b}+\sqrt{c}\)

\(\ge\sqrt{a}+\sqrt{b}+\sqrt{c}+3\sqrt[3]{abc}\)\(=\sqrt{a}+\sqrt{b}+\sqrt{c}+3\)

The total number of candy John and Tom ia:

15+31=46( candies)

Tom need to give to John so that each boy will have the same number of candies is:

31-46:2=8(candies)

Answer: 8 candies.

The total number of candy John and Tom ia:
15+31=46( candies)
Tom need to give to John so that each boy will have the same number of candies is:
31-46:2=8(candies)
Answer: 8 candies

The total candies of John and Tom is:

15 + 31 = 46 (candies)

The number of candies that Tom needs to give John so that each boy will have the same number of candies is:

31 - (46 : 2) = 8 (candies)

                     Answer: 8 candies.

1^st way :10 + 20 + 60 + 40 + 80 + 90

=(1 + 2 + 6 + 4 + 8 + 9) x 10

=30 x 10

=300

2^nd way :10 + 20 + 60 + 40 + 80 + 90

=(10 + 90) + (20 + 80)  + (60 + 40)

=100 + 100 + 100

=100 x 3

=300

10+20+60+40+80+90

=(10+90)+(20+80)+(60+40)

=100+100+100

=300

thank you