1^st way :

99²⁰ = (99²)¹⁰ = 9801¹⁰ < 9999¹⁰

2^nd way :

99²⁰ = 99¹⁰ x 99¹⁰ ; 9999¹⁰ = 99¹⁰ x 101¹⁰

Since 99¹⁰ < 101¹⁰, 99²⁰ < 9999¹⁰

                    Answer:

3^223>3^222=(3^2)^111=9^111

2^322<2^333=(2^3)111=8^111

Form(1) and (2) deduced:2^332<8^111<9^111<3^223

Dress:2^332<3^223

yourself home

There are something not truth here !!! :V

Both of you , phanhuytien and Phan Huy Toàn , are you kidding me ???

Thôi , nói tiếng việt cho dễ 

Bọn bây đùa nhau ak , 2 bài phải nói là rất khác :V , khác như là cá mè một lứa

Chép bài nhau :V , trong bài còn có chỗ ta hơi thắc mắc , "Dress" ở đó nghĩa là j , là "váy, đầm" ak , lên google mà trans á , trans được thì trans , ko trans được thì thôi , ở web này thì ko cần mấy bọn dog nhả xương rồi gặm đâu :v 

Ok , compare :))

We have : \(2^{332}< 2^{333}=\left(2^3\right)^{111}< \left(3^2\right)^{111}=3^{222}< 3^{223}\)

That is too difficult , right =)) 

a) 4xy³ + \(\dfrac{1}{3}\)xy⁸ + \(\dfrac{2}{5}\)xy³ + \(-\dfrac{1}{3}\)xy⁸

= 4xy³ + \(\dfrac{2}{5}\)xy³ + \(\dfrac{1}{3}xy^8\) + \(-\dfrac{1}{3}xy^8\)

= \(\dfrac{14}{3}xy^3+0=\dfrac{14}{3}xy^3\)

a) \(4xy^3+\dfrac{1}{3}xy^8+\dfrac{2}{3}xy^3+\left(-\dfrac{1}{3}\right)xy^8\)

\(=\left(4+\dfrac{2}{3}\right)xy^3+\left[\left(-\dfrac{1}{3}\right)+\dfrac{1}{3}\right]xy^8\)

\(=\dfrac{14}{3}xy^3+0\)

\(=\dfrac{14}{3}.\dfrac{2}{3}.\left(-\dfrac{1}{2}\right)^3=-\dfrac{7}{18}\)

a) 4xy3+13xy8+23xy3+(−13)xy8

=(4+23)xy3+[(−13)+13]xy8

=143xy3+0

=143.23.(−12)3=−71

we need: 28*3=84

we have:84:25=3(remaining 9)

so we need a packet for these 9  sheets of graph of papers

3+1=4 (packets)

answer:4 packets

The number of sheets of graph of paper that the students need is :

3 x 28 = 84

We have : 84 : 25 = 3 with remainder 9

So we need a packet for these 9 sheets of graph of paper.

 Then the answer is : 3 + 1 = 4

we have : \(\dfrac{1}{x}+\dfrac{1}{y}+\dfrac{1}{6xy}=\dfrac{1}{6}\Rightarrow6y+6x+1=xy\)

\(\Rightarrow\left(x-6\right)\left(y-6\right)=37\) 

suppose : \(x\ge y\) then \(\left\{{}\begin{matrix}x-6=-1\\y-6=-37\end{matrix}\right.\) or  \(\left\{{}\begin{matrix}x-6=37\\y-6=1\end{matrix}\right.\)

Case type, the latter case \(x=43\) , \(y=7\)

thanks

Last number is: 998 

The first number: 100 

Số có ba chữ số mà chia hết cho 2 là :

    ( 998 - 100 ) : 2 + 1 = 450 ( numbers )

                                Đ/s : 450 numbers 

Easy you 

The first number is : 100

Last number is : 998

               Number with three digits that share for 2 is :

                              ( 998 - 100 ) : 2 + 1 =  450 ( numbers )

                                           Đ/s : 450 numbers.

     Answer:

9^200=(3^2)^200=3^400

Dress 3^400=9^200

                                                 Answer;

     3^400=(3^4)^1000=81^1000

     9^2000=(9^2)^1000=81^1000

Dress 3^400=9^200

Is Vietnam Maths please post this question in web

https:olm.vn

I'm sorry , i'm wrong at question c !

We have : 

2⁵ = 32 = 2^x

=> x = 5 

a) 2³ = 2^x

<=> \(\dfrac{2^3}{2^x}=1\)

<=> 2^{3 - x} = 1

<=> 3 - x = 0

<=> x = 3

b) 25 = 5^x

<=> 5² = 5^x

=> x = 2

c) 32 = 2^x

<=> 2⁴ = 2^x

<=> x = 4

a,2^3=2^x         b,25=5^x                   c,32=2^x

x=3                      25 =5^2                      32=2^5