# All Questions

##### Lê Quốc Trần Anh Coodinator

16/03 at 11:33##### Lê Quốc Trần Anh Coodinator

16/03 at 11:27-
Tell the pencil is a, the paper clips is b and the eraser is c

=> a + 5b = 2c and a = 29b

=> 29b + 5b = 2c

=> 34b = 2c

=> c = 17b

So 17 paper clips weigh the same as an eraser.

Lê Quốc Trần Anh selected this answer.

##### Lê Quốc Trần Anh Coodinator

16/03 at 11:26-
Tell these number to find is x

=> 100 < x < 1000

=> x has 3 digits.

The hundred-digit has 3 choice

The ten-digit has 3 choice

The units-digit has 3 choice too

So there are 3.3.3 = 27 intergers satisfy

Lê Quốc Trần Anh selected this answer.

##### Lê Quốc Trần Anh Coodinator

16/03 at 11:25-
2

^{2017}. 7^{2017}= 2^{504.4+1}.7^{504.4+1}= ...2*...7 = ...4So the units digit of 2

Lê Quốc Trần Anh selected this answer.^{2017}.7^{2017}is 4

##### Nhi Hạ Băng

16/03 at 08:21-
We have: 4 apples + 6 bananas = 1.56

9 apples + 7 bananas = 2.60

=> 4 apples + 6 bananas + 9 apples + 7 bananas = 1.56 + 2.60

13 apples + 13 bananas = 4.16

=> 1 apple + 1 banana = \(4.16\div13=0.32\)

So the answer is: 0.32

P/s: Sorry I don't know how to do the euro sign.

Nhi Hạ Băng selected this answer.

##### Lê Quốc Trần Anh Coodinator

16/03 at 07:48-
We have: a

^{m}: a^{m}= a^{0}= 1So 0

^{5}: 0^{5}= 0^{5}: 0 undeterminedSo 0

Selected by MathYouLike^{0}undetermined

##### Lê Quốc Trần Anh Coodinator

16/03 at 07:44-
Convert: 6 feet = 72 inch ; 8 feet = 96 inch

So the area of this wall is: 72.96 = 6912 (square-inch)

The area of each tile is: 4.4 = 16 (square-inch)

So there are 6912: 16 = 432 (tiles) are neede to cover all area of this wall

Lê Quốc Trần Anh selected this answer.

##### Lê Quốc Trần Anh Coodinator

16/03 at 07:44-
\(\widehat{ABC}=90^o \Rightarrow O\in AC \\\Rightarrow The\hskip0.1cmlength\hskip0.1cm of\hskip0.1cm arc \hskip0.1cmABC\hskip0.1cmis\\ l= \dfrac12\times2\pi\times3=3\pi \hskip0.1cm(meters)\)

Lê Quốc Trần Anh selected this answer.

##### Lê Quốc Trần Anh Coodinator

16/03 at 07:42-
From the question, we have some equations:

\(\left \{ \begin{array}{l} A+B=150\times 2=300\quad(1)\\ B+C=127\times 2=254\quad (2)\\ C+D=168\times 2 =336\quad(3) \end{array}\right.\)

We do the following operation \((1)+(3)-(2)\). after that, we have \(A+D=300+336-254=382\).

Therefore, the average weight of sheep A and sheep D is: \(382\div 2= 191\)(pounds)

Note that \(A,B,C,D\) is the weight of each sheep A, B, C, D, respectively.

Lê Quốc Trần Anh selected this answer.

##### Lê Quốc Trần Anh Coodinator

16/03 at 07:42-
From the question, we have 3 kinds of meat and 4 kinds of vegatables.

To get a two-distinct-meat pizza, we need to choose the first meat and the second meat.

From 3 kinds of meat, to choose the first meat, we have 3 options. After choosing the first meat, we have 2 kinds left (because the first and the second meat need to be distinct), so we have 2 options for the second meat.

So, we have \(3\times2=6\) two-distinct-meat pizzas.

To get a two-distinct-vegatable pizza, we need to choose the first vegatable and the second vegatable.

From 4 kinds of vegatables, to choose the first vegatable, we have 4 options. After choosing the first vegatable, we have 3 kinds left (because the first and the second vegatable need to be distinct), so we have 3 options for the second vegatable.

So, we have \(4\times3=12\) two-distinct-vegatable pizzas.

To get a one-meat-one-vegatable pizza, we need to choose the meat and the vegatable.

From 3 kinds of meat, we have 3 options. From 4 kinds of vegatables, we have 4 options.

So, we have \(3\times4=12\) one-meat-one-vegatable pizzas.

After all, we have \(6+12+12=30\) combinations of pizza.

Lê Quốc Trần Anh selected this answer.