We have :

\(=\dfrac{\left(x^3+x^2\right)-\left(x+1\right)}{x^2-5x-x+5}\)

\(=\dfrac{x^2\left(x+1\right)-\left(x+1\right)}{x\left(x-1\right)-5\left(x-1\right)}\)

\(=\dfrac{\left(x-1\right)\left(x+1\right)^2}{\left(x-5\right)\left(x-1\right)}\)

\(=\dfrac{\left(x+1\right)^2}{x-5}\)

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