Grade 6
Đỗ Phi Phi
11/01/2018 at 23:12
FA Liên Quân Garena 12/01/2018 at 12:25
Sentence 1: Thanksgiving is always the last Thursday of November

Nguyễn Thị Thanh Hiền 12/01/2018 at 09:39
Sentence 1: Thanksgiving is always the last Thursday of November

nguyễn hồng quân 13/04/2018 at 09:09
câu 1 là đúng
Đỗ Phi Phi
11/01/2018 at 23:07
My answer is C: 6 Đỗ Phi Phi selected this answer.

FA Liên Quân Garena 12/01/2018 at 12:26
(D)8 or (E)9

Nguyễn Thị Thanh Hiền 12/01/2018 at 09:42
(D)8 or (E)9
Đỗ Phi Phi
08/01/2018 at 21:28
FA Liên Quân Garena 08/01/2018 at 21:40
I chose the answer : E

Yuki Judai 20/01/2018 at 06:50
hjh.hj.kjh,jhb,bjv,

Trương Như Hoàng 08/01/2018 at 22:22
I choose D because :
a<b => ab<0 which means ab is negative so I is true.0<a<b => ab>0 => \(\dfrac{1}{ab}\) is positive so II is true.
\(\dfrac{1}{b}\) \(\dfrac{1}{a}\)=\(\dfrac{ab}{ab}\) but ab<0 and ab>0 => \(\dfrac{ab}{ab}\) is negative so III is false
Amano Ichigo
07/10/2017 at 17:50
Help you solve math 07/10/2017 at 17:56
We have : 6x6 , 36x6 , ...
So the result is 6
Amano Ichigo selected this answer.
Amano Ichigo
04/09/2017 at 20:21
Math You Like 04/09/2017 at 20:34
You should post the question in English
Amano Ichigo selected this answer. 
Amano Ichigo 04/09/2017 at 21:01
mk rất khó để viết bài toán bằng tiếng anh bởi vì mk ko bt nhiều về tiếng anh du mk giới
Đỗ Phi Phi
26/07/2017 at 23:22
Because he threw 8 darts at the dartboard => The score must be even. (Odd + Odd = Even)
The most score that he could throw is: \(8.9=72\left(points\right)\)
The least score that he can throw is: \(8.3=24\left(points\right)\)
Satisfy all this operation, only \(C.42\) could be his score.
So the answer is C
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FA KAKALOTS 08/02/2018 at 22:01
Because he threw 8 darts at the dartboard => The score must be even. (Odd + Odd = Even)
The most score that he could throw is: 8.9=72(points)
The least score that he can throw is: 8.3=24(points)
Satisfy all this operation, only C.42
could be his score.
So the answer is C
Đỗ Phi Phi
26/07/2017 at 22:56
Let A,D,H be the age of each person respectively.We have :
\(\circledast A+D+H=49;\circledast D=3H;\circledast A+5=3\left(D+5\right)\)
\(\Rightarrow H=\dfrac{1}{3}D;A=3D+10\)
\(\Rightarrow\left(3D+10\right)+D+\dfrac{1}{3}D=49\Rightarrow\dfrac{13}{3}D=39\Rightarrow D=9\)
\(\Rightarrow H=3;A=37\Rightarrow A.D.H=37.9.3=999\)
So,the product of their ages is 999
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FA KAKALOTS 08/02/2018 at 22:01
Let A,D,H be the age of each person respectively.We have :
⊛A+D+H=49;⊛D=3H;⊛A+5=3(D+5)
⇒H=13D;A=3D+10
⇒(3D+10)+D+13D=49⇒133D=39⇒D=9
⇒H=3;A=37⇒A.D.H=37.9.3=999
So,the product of their ages is 999
Đỗ Phi Phi
26/07/2017 at 22:52Đỗ Phi Phi
26/07/2017 at 22:44
FA KAKALOTS 08/02/2018 at 22:01
Because this topic is not to say that the faces should be different so that their sum is the smallest, then the remaining 3 [can be said to be x, y, z] smallest and satisfy:
 12*x = 9*y = 6*z
=> x = y = z = 0 is the smallest
So the sum is: 0 + 0 + 0 + 6 + 9 + 12 = 27
Answer: 27 
Dao Trong Luan 28/07/2017 at 19:04
Because this topic is not to say that the faces should be different so that their sum is the smallest, then the remaining 3 [can be said to be x, y, z] smallest and satisfy:
 12*x = 9*y = 6*z
=> x = y = z = 0 is the smallest
So the sum is: 0 + 0 + 0 + 6 + 9 + 12 = 27
Answer: 27
Đỗ Phi Phi
26/07/2017 at 22:28
Searching4You 27/07/2017 at 09:29
The answer is 901.
From 1 to 9 we have sum : 45.
From 10 to 19 we have : 1 + 0 + 1 + 1 + 1 + 2 + 1 + 3 +...+ 1 + 9 we have sum 55.
Next from 20 to 29 we have sum 65.
................. 30 to 39 we have sum 75.
................. 40 to 49 we have sum 85.
................. 50 to 59 we have sum 95.
................. 60 to 69 we have sum 105.
................. 70 to 79 we have sum 115.
................. 80 to 89 we have sum 125.
................. 90 to 99 we have sum 135.
And the last 100 we have sum 1 + 0 + 0 = 1.
So the sum she obtained is : 65 + 75 + 85 + 95 +105 +115 +125 +135 + 1 = 901.
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FA KAKALOTS 08/02/2018 at 22:01
The answer is 901.
From 1 to 9 we have sum : 45.
From 10 to 19 we have : 1 + 0 + 1 + 1 + 1 + 2 + 1 + 3 +...+ 1 + 9 we have sum 55.
Next from 20 to 29 we have sum 65.
................. 30 to 39 we have sum 75.
................. 40 to 49 we have sum 85.
................. 50 to 59 we have sum 95.
................. 60 to 69 we have sum 105.
................. 70 to 79 we have sum 115.
................. 80 to 89 we have sum 125.
................. 90 to 99 we have sum 135.
And the last 100 we have sum 1 + 0 + 0 = 1.
So the sum she obtained is : 65 + 75 + 85 + 95 +105 +115 +125 +135 + 1 = 901.

From 1 to 9 the sum of the individual digits are: \(1+2+3+4+5+6+7+8+9=45\)
From 10 to 19: the tens digit all have the same digit, the ones digit have the rules from 1 to 9.
So as the same with 2099.
The number 100 has the individual digits sum: \(1+0+0=1\)
She has obtained the sum: \(\left[\left(1+2+3+4+5+6+7+8+9\right).10\right]+\left[\left(1+2+3+4+5+6+7+8+9\right).10\right]+1\)
\(=450+450+1=901\)
So she obtained the sum: \(901\)
Đỗ Phi Phi
26/07/2017 at 22:25
Searching4You 27/07/2017 at 09:39
It's a good problem :((
So we have the time is \(\dfrac{2}{60}\left(hour\right)=\dfrac{1}{30}\)
So we have the speed to get to each intersection right on the first time is : \(\dfrac{3,5}{x}=\dfrac{1}{30}\Rightarrow x=105\) (kilometres per hour).
So he can travel to get to each intersection at the third time as it just changes to green at the speed of \(\dfrac{105}{3}=35\) (kilometres per hour)
That's what I think :))
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FA KAKALOTS 08/02/2018 at 22:02
It's a good problem :((
So we have the time is 260(hour)=130
So we have the speed to get to each intersection right on the first time is : 3,5x=130⇒x=105
(kilometres per hour).
So he can travel to get to each intersection at the third time as it just changes to green at the speed of 1053=35
(kilometres per hour)
That's what I think :))
Đỗ Phi Phi
26/07/2017 at 22:18Đỗ Phi Phi
26/07/2017 at 22:14Đỗ Phi Phi
26/07/2017 at 22:09Đỗ Phi Phi
26/07/2017 at 21:59
We put the numbers 12 ; 34 and 56 opposite each other. So then 23 and 45 will have the same side. So he will lose at least 2 points.
So the answer is: \(C:2points.\)
Đỗ Phi Phi
26/07/2017 at 21:56
ohhh.....! I'm sorry , the last row will be :
So , there are 120 kilometres do you live from the station .
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FA KAKALOTS 08/02/2018 at 22:02
Let {V1=4V2=20
(km/h)
We got this :
S=V.t
(with t is the time , S is the length of roads and V is the speed)
⇒⎧⎪ ⎪ ⎪⎨⎪ ⎪ ⎪⎩t1=SV1t2=SV2
From the topic :
t1=t2+24
(minute)
⇔SV1=SV2+24
⇔S4=S20+24
⇔S4=S+24.2020
<=> 20S = 4S + 4.20.24
<=> 16S = 4.20.24
<=> S = 120 (km)
So , there are 20 kilometres do you live from the station .

Let \(\left\{{}\begin{matrix}V_1=4\\V_2=20\end{matrix}\right.\) (km/h)
We got this :
\(S=V.t\) (with t is the time , S is the length of roads and V is the speed)
\(\Rightarrow\left\{{}\begin{matrix}t_1=\dfrac{S}{V_1}\\t_2=\dfrac{S}{V_2}\end{matrix}\right.\)
From the topic :
\(t_1=t_2+24\) (minute)
\(\Leftrightarrow\dfrac{S}{V_1}=\dfrac{S}{V_2}+24\)
\(\Leftrightarrow\dfrac{S}{4}=\dfrac{S}{20}+24\)
\(\Leftrightarrow\dfrac{S}{4}=\dfrac{S+24.20}{20}\)
<=> 20S = 4S + 4.20.24
<=> 16S = 4.20.24
<=> S = 120 (km)
So , there are 20 kilometres do you live from the station .
Đỗ Phi Phi
26/07/2017 at 21:49Đỗ Phi Phi
26/07/2017 at 21:45
Lý Tiểu Phi Đao Không Bằng Mình Tao Phi Dép 27/07/2017 at 07:08
No isosceles triangles . Because 2 < 3 < 7 < 11
There is no equal edge
Đỗ Phi Phi
26/07/2017 at 21:28
Convert : 1/2 hour = 30 minutes
The number of minutes it takes Maya to finish her homework questions is : \(30:\dfrac{1}{3}=90\)
The number of minutes it takes Mây to finish the remaining questions is : 90  30 = 60
So,the answer is 60 minutes
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FA KAKALOTS 08/02/2018 at 22:03
Convert : 1/2 hour = 30 minutes
The number of minutes it takes Maya to finish her homework questions is : 30:13=90
The number of minutes it takes Mây to finish the remaining questions is : 90  30 = 60
So,the answer is 60 minutes