integers
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Lux Arcadia 14/06/2019 at 14:20\(\dfrac{n-17}{n+23}=\dfrac{n+23-40}{n+23}=1-\dfrac{40}{n+23}\)
\(\Rightarrow\left\{{}\begin{matrix}40⋮\left(n+23\right)\\n+23\ge23\left(n\ge0\right)\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(n+23\right)\in\left\{1;2;4;5;8;10;20;40\right\}\\n+23\ge23\end{matrix}\right.\)
\(\Leftrightarrow n+23=40\Leftrightarrow n=17\)
Mr. Bee moderators
25/09/2018 at 09:30
such that 
is divisible by 
.
