Problem: A and B have 88 marbles, B has 23 marbles. How many marbles does A have?

Solution: A has the number of marbles is: 88 - 23 = 65 ( marbles)

Answer: 65 marbles 

Vấn đề:Một cái hộp có 88 viên bi,trong đó số viên bi đen là 23.Tính tỉ số phần trăm số bi còn lại so với số bi trong hộp.

Giải:

  số bi còn lại là

       88-23=65 viên

  tỉ số phần trăm giữa số bi còn lại và số bi trong hộp là

         65:88x100=73,86%

                    đ/s:73,86%

After using strawberries to make cake and make juice, Anna's strawberries left is: 

708-12-20=676(strawberries)

Anna is only has:

676:708\(\approx0,95=95\%\)

95% nha

C1 : Lê Quốc Trần Anh and Đào Trọng Luân

C2:

There are : 100% - 25% = 75% (students) are good students

There are all good students : 900 . 75% = 675 (students) are good students

There are: \(900.25\%=225\left(students\right)\)are weak students

So there are: \(900-225=675\left(students\right)\) are good students

675

hk tốt

The number of 5A field was developed are:

       180 : 100 x 45% = 81 ( trees ) 

Number of 5A plants to be planted is :

        180 - 81 = 99 ( trees )

                      Đ/S: 99 trees 

Wish you good study 

eighty-one trees

eighty-one trees

First 25 tons of iron ore contain :

25 : 100 x 72 = 18 (tons of iron)

Second 25 tons of iron ore contain :

25 : 100 x 60 = 15 (tons of iron)

The mixture of iron ore weighs :

25 + 25 = 50 (tons)

The mixture of iron ore contains :

18 + 15 = 33 (tons of iron)

The percentage of iron to the mixture is :

33 : 50 = 66 : 100 = 66%

The percentage of iron ore to the mixture is :

100% - 66% = 34%

First 25 tons of iron ore contain :

25 : 100 x 72 = 18 (tons of iron)

Second 25 tons of iron ore contain :

25 : 100 x 60 = 15 (tons of iron)

The mixture of iron ore weighs :

25 + 25 = 50 (tons)

The mixture of iron ore contains :

18 + 15 = 33 (tons of iron)

The percentage of iron to the mixture is :

33 : 50 = 66 : 100 = 66%

The percentage of iron ore to the mixture is :

100% - 66% = 34%

34%'

ok 

Change: 30%=310

Linda kept: 1−(15+310)=12

 of the 100 dollars as cash.

Change: \(30\%=\dfrac{3}{10}\)

Linda kept: \(1-\left(\dfrac{1}{5}+\dfrac{3}{10}\right)=\dfrac{1}{2}\) of the 100 dollars as cash.

have : 30%=\(\dfrac{3}{10}\)

Linda kept : 1-(1/5+3/10)=1/2 

Answer : Linda kept 1/2 of the 100 dollars as cash