Permutation and combination
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There are: \(3\times2\times5=30\)combinations
Selected by MathYouLike
falcon handsome moderators
17/04/2017 at 11:28-
FA KAKALOTS 09/02/2018 at 21:43Arrcoding to the context, 4 balls must be put into 4 different tubes that each tube must have a ball. So the free balls are: 7−4=3(balls)
There are: 6.3=18(ways)
divided by 1 free ball/tube.
There are: 4.3.3=36(ways)
divided by 2 free ball/tube.
There are: 4.1=4(ways)
divided by 3 free ball/tube.
There are total: 18+36+4=58(ways)
ANSWER: 58 ways
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Arrcoding to the context, 4 balls must be put into 4 different tubes that each tube must have a ball. So the free balls are: \(7-4=3\left(balls\right)\)
There are: \(6.3=18\left(ways\right)\) divided by 1 free ball/tube.
There are: \(4.3.3=36\left(ways\right)\) divided by 2 free ball/tube.
There are: \(4.1=4\left(ways\right)\)divided by 3 free ball/tube.
There are total: \(18+36+4=58\left(ways\right)\)
ANSWER: 58 ways
falcon handsome moderators
17/04/2017 at 11:31
falcon handsome moderators
17/04/2017 at 11:29-
FA KAKALOTS 09/02/2018 at 21:44
The number of ways to put 4 letters into 5 letter boxes is :
|P45=5!(5−4)!=120
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The number of ways to put 4 letters into 5 letter boxes is :
\(|P^4_5=\dfrac{5!}{\left(5-4\right)!}=120\)
taylor swift
31/03/2017 at 20:43
taylor swift
31/03/2017 at 20:33
taylor swift
31/03/2017 at 20:30-
There are : (200 - 1) : 1 + 1 = 200 numbers from 1 to 200
We have a sequence of two-digit numbers are as follows :
2 ; 12 ; 22 ; 32 ; ....... ; 192
Apply a formula to count numbers , we have :
(192 - 2) : 10 + 1 = 20
There are also numbers with 2 digits such as
20 ; 21 ; 23 ; 24 ; .... ; 29 ; 120 ; 121 ; 122 ; 123 ; ...... 129
And there are have 18 also numbers .
So , from these information , we have 38 numbers have digit 2
We have :
200 - 38 = 162 (numbers)
There are 162 numbers from 1 to 200 do not have the digit 2
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Kokone 04/04/2017 at 14:18There are : (200 - 1) : 1 + 1 = 200 numbers from 1 to 200
We have a sequence of two-digit numbers are as follows :
2 ; 12 ; 22 ; 32 ; ....... ; 192
Apply a formula to count numbers , we have :
(192 - 2) : 10 + 1 = 20
There are also numbers with 2 digits such as
20 ; 21 ; 23 ; 24 ; .... ; 29 ; 120 ; 121 ; 122 ; 123 ; ...... 129
And there are have 18 also numbers .
So , from these information , we have 38 numbers have digit 2
We have :
200 - 38 = 162 (numbers)
There are 162 numbers from 1 to 200 do not have the digit 2
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Nguyen Van Hung 27/06/2017 at 20:34
There are : (200 - 1) : 1 + 1 = 200 numbers from 1 to 200
We have a sequence of two-digit numbers are as follows :
2 ; 12 ; 22 ; 32 ; ....... ; 192
Apply a formula to count numbers , we have :
(192 - 2) : 10 + 1 = 20
There are also numbers with 2 digits such as
20 ; 21 ; 23 ; 24 ; .... ; 29 ; 120 ; 121 ; 122 ; 123 ; ...... 129
And there are have 18 also numbers .
So , from these information , we have 38 numbers have digit 2
We have :
200 - 38 = 162 (numbers)
There are 162 numbers from 1 to 200 do not have the digit 2 .
falcon handsome moderators
31/03/2017 at 17:35-
a) There are :7 x 7 x 6 x 5 = 1470 numbers
b) There are :4 x 4 x 3 x 2 = 96 even numbers
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FA KAKALOTS 09/02/2018 at 21:45
a) There are :7 x 7 x 6 x 5 = 1470 numbers
b) There are :4 x 4 x 3 x 2 = 96 even numbers
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Kokone 04/04/2017 at 14:18
a) There are :7 x 7 x 6 x 5 = 1470 numbers
b) There are :4 x 4 x 3 x 2 = 96 even numbers
falcon handsome moderators
31/03/2017 at 17:14-
a) There are : 7 x 7 x 6 x 5 = 1470 numbers
b) There are : 4 x 3 x 2 x 1 = 24 old numbers
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FA KAKALOTS 09/02/2018 at 21:45
ANSWER :
a,There are : 7 x 7 x 6 x 5 = 1470 ( numbers )
b,There are : 4 x 3 x 2 x 1 = 24 ( old numbers )
[hiu] Easy,right ?
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Cố Lên Nào Các Bạn 08/04/2017 at 10:53ANSWER :
a,There are : 7 x 7 x 6 x 5 = 1470 ( numbers )
b,There are : 4 x 3 x 2 x 1 = 24 ( old numbers )
Easy,right ?
