Prime Numbers and Composite Numbers
Đỗ Phi Phi
26/07/2017 at 21:39-
2 x 2 + 1 = 5
3 x 2 + 1 = 7
5 x 2 + 1 = 11
7 x 2 + 1 = 15
11 x 2 + 1 = 23
13 x 2 + 1 = 27
So,there are 4 jillyprimes which are less than 15 : 2 ; 3 ; 5 ; 11
Selected by MathYouLike -
FA KAKALOTS 28/01/2018 at 22:042 x 2 + 1 = 5
3 x 2 + 1 = 7
5 x 2 + 1 = 11
7 x 2 + 1 = 15
11 x 2 + 1 = 23
13 x 2 + 1 = 27
So,there are 4 jillyprimes which are less than 15 : 2 ; 3 ; 5 ; 11
steve jobs
27/03/2017 at 11:05
steve jobs
27/03/2017 at 10:56
steve jobs
27/03/2017 at 10:56
steve jobs
27/03/2017 at 10:54
steve jobs
27/03/2017 at 10:53
steve jobs
27/03/2017 at 10:52-
»ﻲ2004#ﻲ« 29/03/2017 at 06:10We have : abcabc = abc x 1001 = abc x 7 x 11 x 13
Because abc is a prime number,the number of divisors of abcabc is :
(1 + 1)4 = 16
-
Number One 02/04/2017 at 06:29We have : abcabc = abc x 1001 = abc x 7 x 11 x 13Because abc is a prime number,the number of divisors of abcabc is :
(1 + 1)4 = 16
-
Phạm Tuấn Kiệt 18/05/2017 at 19:49We have : abcabc = abc x 1001 = abc x 7 x 11 x 13
Because abc is a prime number,the number of divisors of abcabc is :
(1 + 1)4 = 16
steve jobs
27/03/2017 at 10:51-
Nguyễn Nhật Minh 01/06/2017 at 12:23Your problem is not true, because 3210 = 2 x 3 x 5 x 107, and noone in this problem can be 107 years old!
Bill gates
20/03/2017 at 10:51
Bill gates
20/03/2017 at 10:49-
Run my EDM 20/03/2017 at 12:40\(300=2^2.3.5^2\)
The number of integer factors 300 have is \(2.\left[\left(2+1\right)\left(1+1\right)\left(2+1\right)\right]=36\)
Ans : 36.
Selected by MathYouLike -
→இے๖ۣۜQuỳnh 22/03/2017 at 20:18You have : 300 = 22.3.52
The number of integer factors 300 have is :
2.[(2 + 1)(1 + 1)(2 + 1)] = 36
Answer : 36. good
-
»ﻲ†hïếu๖ۣۜGïลﻲ« 25/03/2017 at 18:59
We have : 300 = 22.3.52
The number of integer factors 300 have is :
2.[(2 + 1)(1 + 1)(2 + 1)] = 36
Answer : 36. good
Bill gates
20/03/2017 at 10:49-
¤« 24/02/2018 at 13:57
We have : 37 = 3 + 5 + 29 (c1)
37 = 3 + 11 + 23 (c2)
37 = 5 + 13 + 19 (c3)
Drees is three ways are there to write 37
-
Lê Nho Khoa 23/03/2017 at 21:07We have : 37 = 3 + 5 + 29 (c1)
37 = 3 + 11 + 23 (c2)
37 = 5 + 13 + 19 (c3)
Drees is three ways are there to write 37
-
Nguyễn Việt Hoàng 21/03/2017 at 06:12We have : 37 = 3 + 5 + 29 (c1)
37 = 3 + 11 + 23 (c2)
37 = 5 + 13 + 19 (c3)
Drees is three ways are there to write 37
Bill gates
20/03/2017 at 10:48-
¤« 24/02/2018 at 13:57
We have : 7m + n = mn + 11
=> 7m + n - mn = 11
=> m(7 - n) - 7 + n = 4
=> (m - 1)(7 - n) = 4
So we have a table as shown :
m - 1 1 2 4
7 - n 4 2 1
m 2 3 5
n 3 5 6 (absurd)
7m + n 17 26 (absurd) xHence,we have m = 2 ; n = 3 and m2 + n2 = 13
-
We have : 7m + n = mn + 11
=> 7m + n - mn = 11
=> m(7 - n) - 7 + n = 4
=> (m - 1)(7 - n) = 4
So we have a table as shown :
m - 1 1 2 4 7 - n 4 2 1 m 2 3 5 n 3 5 6 (absurd) 7m + n 17 26 (absurd) x Hence,we have m = 2 ; n = 3 and m2 + n2 = 13
Bill gates
20/03/2017 at 10:46-
¤« 24/02/2018 at 13:57
Only 1997 is a prime number
-
Only 1997 is a prime number
