# Rate and Speed

##### Uchiha Sasuke

06/04/2019 at 01:52-
Trà Châu Giang 13/04/2019 at 07:17
giúp mik với các bạn học giỏi ơi huhuhu

##### Đỗ Phi Phi

26/07/2017 at 22:25-
Searching4You 27/07/2017 at 09:39
It's a good problem :((

So we have the time is \(\dfrac{2}{60}\left(hour\right)=\dfrac{1}{30}\)

So we have the speed to get to each intersection right on the first time is : \(\dfrac{3,5}{x}=\dfrac{1}{30}\Rightarrow x=105\) (kilometres per hour).

So he can travel to get to each intersection at the third time as it just changes to green at the speed of \(\dfrac{105}{3}=35\) (kilometres per hour)

That's what I think :))

Selected by MathYouLike -
FA KAKALOTS 08/02/2018 at 22:02
It's a good problem :((

So we have the time is 260(hour)=130

So we have the speed to get to each intersection right on the first time is : 3,5x=130⇒x=105

(kilometres per hour).

So he can travel to get to each intersection at the third time as it just changes to green at the speed of 1053=35

(kilometres per hour)

That's what I think :))

##### Đào Nhật Hiển

18/07/2017 at 10:23-
Lâm Phan Bình Nguyên 26/07/2017 at 14:30
The length of train B is equal to the distance two train travelled in 6 seconds.

48x2=96

96km/h=80/3 m/s

The length of train B=6x80/3=160m