square root
Summer Clouds moderators
19/07/2017 at 09:07-
Aim Egst 19/07/2017 at 10:46\(A=\sqrt{2-\sqrt{3}}+\sqrt{2+\sqrt{3}}\)
\(A^2=2-\sqrt{3}+2+\sqrt{3}+2\sqrt{\left(2-\sqrt{3}\right)\left(2+\sqrt{3}\right)}\)
\(A^2=4+2\sqrt{2^2-\sqrt{3}^2}\)
\(A^2=4+2\sqrt{4-3}=4+2=6\)
\(\Rightarrow A^2=6\Rightarrow A=\sqrt{6}\)
Select A
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FA KAKALOTS 08/02/2018 at 21:58A=√2−√3+√2+√3
A2=2−√3+2+√3+2√(2−√3)(2+√3)
A2=4+2√22−√32
A2=4+2√4−3=4+2=6
⇒A2=6⇒A=√6
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Nguyễn Huy Hoàng 22/08/2017 at 09:10Số nguyên dương chia hết cho cả 7 là
